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How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
What is the vertex of the equation Y equals 4X squared minus 8Xplus 9?
To find the vertex of the quadratic equation ( Y = 4X^2 - 8X + 9 ), we can use the vertex formula ( X = -\frac{b}{2a} ). Here, ( a = 4 ) and ( b = -8 ), so ( X = -\frac{-8}{2 \times 4} = 1 ). Substituting ( X = 1 ) back into the equation gives ( Y = 4(1)^2 - 8(1) + 9 = 5 ). Therefore, the vertex of the equation is at the point ( (1, 5) ).
What order pairs to equation x minus 2x equals negative 4 and equation 2x minus y equals 1?
x = 4 and y = 7
What are the order pairs to equation x minus 2x equals negative 4 and equation 2x minus y equals 1?
x = 4 and y = 7 which will satisfy both equations
What is the y coordinate of the vertex of the parabola that is given y equals negative 2 point 5 parenthese x minus 4 parenthese end squared minus 5?
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
What is the vertex of the quadratic equation y equals x squared minus x plus 72?
(1/2, 71 and 3/4)or(0.5, 71.75)
What are the coordinates of the vertex of the function below y minus 11 equals negative x minus 5 to the second power?
The vertex is (5, 11).
What are the coordinates of the vertex y equals x plus 2 minus 4?
y = x + 2 - 4 is the same as y = x - 2 which is the equation of a straight line. A single straight line cannot have a vertex.
What is the vertex of the equation Y equals 4X squared minus 8Xplus 9?
To find the vertex of the quadratic equation ( Y = 4X^2 - 8X + 9 ), we can use the vertex formula ( X = -\frac{b}{2a} ). Here, ( a = 4 ) and ( b = -8 ), so ( X = -\frac{-8}{2 \times 4} = 1 ). Substituting ( X = 1 ) back into the equation gives ( Y = 4(1)^2 - 8(1) + 9 = 5 ). Therefore, the vertex of the equation is at the point ( (1, 5) ).
What is the vertex of the parabola given by the equation x equals negative 4 times y minus 3 squared plus 2?
Question can be taken as multiple meanings. Please see discussion.
What is the equation for minus 7x equals 63?
The required equation is: -7x = 63
What order pairs to equation x minus 2x equals negative 4 and equation 2x minus y equals 1?
x = 4 and y = 7
How do you graph y equals x squared minus 4?
its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.
What statement can you make about the number of diagonals that can be drawn from one vertex in a polygon?
Number of sides minus two equals number of diagonals drawn from one vertex.
What are the order pairs to equation x minus 2x equals negative 4 and equation 2x minus y equals 1?
x = 4 and y = 7 which will satisfy both equations
What is the y coordinate of the vertex of the parabola that is given y equals negative 2 point 5 parenthese x minus 4 parenthese end squared minus 5?
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).
