It is the average of -2 and +6, that is, x = 2
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
To find the vertex of the quadratic equation ( Y = 4X^2 - 8X + 9 ), we can use the vertex formula ( X = -\frac{b}{2a} ). Here, ( a = 4 ) and ( b = -8 ), so ( X = -\frac{-8}{2 \times 4} = 1 ). Substituting ( X = 1 ) back into the equation gives ( Y = 4(1)^2 - 8(1) + 9 = 5 ). Therefore, the vertex of the equation is at the point ( (1, 5) ).
x = 4 and y = 7
x = 4 and y = 7 which will satisfy both equations
An equation where x equals 3.
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
(1/2, 71 and 3/4)or(0.5, 71.75)
The vertex is (5, 11).
y = x + 2 - 4 is the same as y = x - 2 which is the equation of a straight line. A single straight line cannot have a vertex.
Question can be taken as multiple meanings. Please see discussion.
The required equation is: -7x = 63
x = 4 and y = 7
its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.
Number of sides minus two equals number of diagonals drawn from one vertex.
x = 4 and y = 7 which will satisfy both equations
An equation where x equals 3.
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).