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The vertex of the quadratic function ( y = -11x^2 ) is located at the point (0, 0). This is because the function is in standard form ( y = ax^2 + bx + c ), where ( a = -11 ), ( b = 0 ), and ( c = 0 ). Since there are no linear or constant terms, the vertex is at the origin, which is also the maximum point of this downward-opening parabola.
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Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is the vertex for y equals X raised to the second power?
The vertex is the origin, (0,0).
What is the vertex of y equals x plus 1?
y = x +1 is the equation of a straight line and so has no vertex.
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
What is the vertex of the function y equals x squared plus 4?
The vertex is at the point (0, 4).
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is the vertex for y equals X raised to the second power?
The vertex is the origin, (0,0).
What is the vertex of y equals x plus 1?
y = x +1 is the equation of a straight line and so has no vertex.
What is the vertex of the equation y equals 2x-1?
3
What is the vertex of y equals x-3 plus 2?
The equation is linear and so has no vertex.
What is the vertex of the function y equals x squared plus 4?
The vertex is at the point (0, 4).
What is the vertex when Y equals X squared - 3?
(0, -3)
What is the vertex of the parabola y equals x2 plus 8x plus 5?
The vertex has a minimum value of (-4, -11)
Which is the vertex for y equals 2x - 7?
-5
What is the vertex of y equals x2-6x plus 6?
(3, -21)
What is the x-coordinate of the vertex of y equals 4x - 12 - 3?
y=4x-12-3 is the equation of a straight line. It does not have a vertex. Did you mean y=x squared - 12x - 3 ?
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
