y = X^2 + 4X - 3
set polynomial = to 0
X^2 + 4X - 3 = 0
add 3 to each side
X^2 + 4X = 3
complete the square. take linear term (4) halve it, square it and add constant to other side, factor quadratic term
(X + 2)^2 = 7
subtract 7 from each side
(X + 2) - 7 = 0
Vertex = (-2,-7)
My TI-84 confirms this vertex with original equation
Chat with our AI personalities
The vertex is at (-1,0).
The vertex has a minimum value of (-4, -11)
(3, -21)
-2-5
The vertex of the positive parabola turns at point (-2, -11)