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-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x2 - 6x - 16 = (x - 8)(x + 2)
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
4x+8
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x2-6x+8 = (x-2)(x-4) when factored
x2 - 6x - 16 = (x - 8)(x + 2)
x2 + 6x + 8 = (x + 4)(x + 2)
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
4x+8
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
x2 + 6x + 8
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)