x2 + x - 30 = (x + 6)(x - 5)
x = +5 or -5
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
(x - 1)(x - 14)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
x2+15x+14 = (x+1)(x+14)
You can't factor it
x2 + x - 30 = (x + 6)(x - 5)
x = +5 or -5
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x + 7)(x + 8)
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
The correct classification of x2 15x is a monomial.
x2 + x2 = 2x2
(2 pi) x sqrt(30)
(x-11)(x-4)