Very close to -0.70348
i (taken to be sqrt(-1) for this question) requires that you know a bit about writing complex numbers. i = e^(i*pi/2) so i^i = (e^(i*pi/2))^i which equals e^(i*i*pi/2) since i*i = -1 we get e^(-pi/2) so i^i = e^(-pi/2) which is roughly .207879576
e^x - 2 = 8 e^x = 10 So x = ln(10) = 1/log10(e)
Y = ex(x + 2) Y = ex/(X + 2) =========
13=e+2 11=e (subtract 2 from each side)
m = e*c-2
Real power = voltage x current x power factor.
The power law of indices says: (x^a)^b = x^(ab) = x^(ba) = (x^b)^a → e^(2x) = (e^x)² but e^x = 2 → e^(2x) = (e^x)² = 2² = 4
e to the power -2 = 2.71828183 to power -2 = 0.135335283
i (taken to be sqrt(-1) for this question) requires that you know a bit about writing complex numbers. i = e^(i*pi/2) so i^i = (e^(i*pi/2))^i which equals e^(i*i*pi/2) since i*i = -1 we get e^(-pi/2) so i^i = e^(-pi/2) which is roughly .207879576
e^x - 2 = 8 e^x = 10 So x = ln(10) = 1/log10(e)
Y = ex(x + 2) Y = ex/(X + 2) =========
m = E/c^2
P = E * I Power (watts) equals voltage (E) times current (I)
13=e+2 11=e (subtract 2 from each side)
Because Euler proved it! (No, I can't!)
R = 65*e-5k = 65/(0.006738)k
m = e*c-2