if you meant it as you wrote it, then the equation is just a line.
if you meant: 2x^2-12x+16, then:
y=2(x^2-6x)+16
y=2(x^2-6x+9)+16-18. You have to subtract 18, not 9, because it is being multiplied by 2.
y=2(x-3)^2 - 2
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The vertex of the positive parabola turns at point (-2, -11)
The vertex is at (-1,0).
The vertex has a minimum value of (-4, -11)
The equation is linear and so has no vertex.
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.