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The smallest number that can be subtracted from 1294, yielding a result that when divided by 9, 11, and 13 leaves a remainder of 6 is 1. To prove this, run the following snippit of a program

int i;

for (i=1294; i!= 0; i--)

if (i % 9 6) break;

printf("%u", 1294-i);

another way to prove it it to multiply 9 11 and 13, yielding 1287, adding six, yielding 1293, which is one away from 1294.

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Related Questions

What least number should be subtracted from 86295031 so that the remainder is exactly divisible by 582?

To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.


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