The smallest number that can be subtracted from 1294, yielding a result that when divided by 9, 11, and 13 leaves a remainder of 6 is 1. To prove this, run the following snippit of a program
int i;
for (i=1294; i!= 0; i--)
if (i % 9 6) break;
printf("%u", 1294-i);
another way to prove it it to multiply 9 11 and 13, yielding 1287, adding six, yielding 1293, which is one away from 1294.
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
To find the least number that must be subtracted from 13601 to make it exactly divisible by 87, we first calculate the remainder when 13601 is divided by 87. Performing the division, we find that ( 13601 \div 87 ) gives a quotient of 155 and a remainder of 26. To make 13601 divisible by 87, we need to subtract this remainder from 13601. Therefore, we need to subtract 26, resulting in ( 13601 - 26 = 13575 ), which is exactly divisible by 87.
810: quotient 1, remainder 1
1005
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
what least number must be subtracted from 13081 to get a number exactly divisible by 87
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
To find the least number that must be subtracted from 13601 to make it exactly divisible by 87, we first calculate the remainder when 13601 is divided by 87. Performing the division, we find that ( 13601 \div 87 ) gives a quotient of 155 and a remainder of 26. To make 13601 divisible by 87, we need to subtract this remainder from 13601. Therefore, we need to subtract 26, resulting in ( 13601 - 26 = 13575 ), which is exactly divisible by 87.
810: quotient 1, remainder 1
The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.The number to be subtracted is 11.
1005
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).