Want this question answered?
Assume that f:S->T is invertible with inverse g:T->S, then by definition of invertible mappings f*g=i(S) and g*f=i(T), which defines f as the inverse of g. So g is invertible.
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
I can give you an example and prove it: eg. take the rational no. 2......hence its additive inverse ie. its opposite no. will be -2 now lets add: =(2)+(-2) =2-2 =0 it means that the opposite no.s. get cancelled and give the answer 0 this is the same case for sum of a rational no. and its opposite no. to be ZERO
I posted this question myself to be honest because i wasn't sure... but the horizontal line test was made to prove whether the function/graph was an one-to-one function
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
Mulltiplication and division are inverse processes for the same numbers involved in the operation. If my answer is not correct wait please for the edition of this question by an expert. Thank you.
Pio
this question on pic
There is not much to prove there; opposite numbers, by which I take you mean "additive inverse", are defined so that their sum equals zero.
A mathematical rule can be called many things including a theory. Proofs can prove this theory to be a rule.
assume its not. make two cases show that the two cases are equal
Answer this question… Which term best describes a proof in which you assume the opposite of what you want to prove?
Assume that f:S->T is invertible with inverse g:T->S, then by definition of invertible mappings f*g=i(S) and g*f=i(T), which defines f as the inverse of g. So g is invertible.
Unemployment
yes
false
yes it is true