48
That is a good answer but to get ALL answers - do the following:
12 = 3*4
16 = 4*4
Therefore 3*4*4 is the minimum number that is needed.
So to get all numbers
m*3^k*4^p
where m and k is any integer >0 and p is any integer >1
The first number that 12 and 16 go into is 48.
48
Any multiple of 60. There are an infinite number of them.
Any multiple of 208.
The number that can go into both 14 and 16 is their greatest common divisor (GCD), which is 2. This means that 2 is the largest number that divides both 14 and 16 without leaving a remainder. Additionally, other numbers like 1 can also divide both, but 2 is the largest among them.
The first number that 12 and 16 go into is 48.
Not as a whole number because 12/16 = 0.75
1, 2 and 4
16
12:12,24,36,48,60,72,84,96,108,120 14:14,28,32,46,60,74,88,102,116,130 16:16,32,48,64,80,96,112,128,144,160
It is: 1
Only the number 1.
48
The LCM of the numbers 6 and 12 is 12. This is lowest number that will go into both number evenly.
Any multiple of 60. There are an infinite number of them.
Any multiple of 208.
How about 60 as an example