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What is the least number divisible by 2 3 4 5 9 10?
180 is divisible by 2, 3, 4, 5, 9, and 10.
What two numbers are divisible by 2 and 3 and 5 and 6 but are not divisible by 9 or 10?
Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.
Is the number 432 divisible by 2 3 5 6 9 10?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
Is 927 divisible by 2 3 5 9 10?
To determine if 927 is divisible by a number, we need to check if it can be evenly divided by that number without leaving a remainder. 927 is divisible by 3 because the sum of its digits (9 + 2 + 7 = 18) is divisible by 3, which means 927 is also divisible by 3. However, 927 is not divisible by 2, 5, 9, or 10 because it does not end in 0 or 5 for 2 and 5, and it does not have all the factors of 9 or 10.
Is 1845 divisibe by 2 3 5 6 9 10?
Since 1845 is an odd number, it can't be divisible by 2, 6 or 10. It is divisible by 3, 5 and 9.
