y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2
16y-9y3 = 0 y*(16-9y2) = 0 y*(4-3y)*(4+3y) = 0 So y = 0 or (4-3y) = 0 or (4+3y) = 0 ie y = 0 or y = 4/3 or y = -4/3
28y - 16y = 12y.
80
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
6xy/16y = 3x/8 (as long as y≠0) = 3/8x
4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2
16y-9y3 = 0 y*(16-9y2) = 0 y*(4-3y)*(4+3y) = 0 So y = 0 or (4-3y) = 0 or (4+3y) = 0 ie y = 0 or y = 4/3 or y = -4/3
It is: 28y -16y = 12y
It is: 28y -16y = 12y
16y -64 as an inequality = -48
28y - 16y = 12y.
80
4xy/0.25x = 16y
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
x^2 plus 16y?