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Q: What are three consecutive integers whose sum is 126?

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41, 42 and 43

The two even consecutive integers are: 62+64 = 126

The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.

41+42+43=126.

41,42,43

The integers are are 41, 42 and 43.

63+83=126.... hope it helps!

41+42+43 = 126

The numbers are 62 and 64 are two consecutive integers that equal 126.

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

Divide 126 by 2 and choose the even numbers on both sides.

124+125+126=375

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