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U5 = a + 4d = 5

U7 = a + 6d = 3

Subtracting the first equation from the second gives

2d = -2 therefore d = -1

and then a + 4d = 5 implies that a = 9.

So Sn = n/2*{2a + (n-1)*d}

thus S10 = 10/2*{18 + 9*(-1)}

= 5*{9} = 45

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