yes the momentum of it is the same because P initial = P final ALWAYS!
liner momentum = p = mV = 2 kg * 10 m/s = 20 kg m/s
(-)11,666.67 N. To calculate this, you need to use the impulse-momentum principle, whereby the change in momentum is equal to the force multiplied by the time over which the force is applied. The change in momentum here is the final speed x the mass - the initial speed x the mass. Then divide the answer by the time (six seconds) and the answer will be the force applied (in this case the answer is negative as the force is applied in the direction opposite to the direction of the truck's motion.)
take the box off the truck and get in the back before hits wall get target
The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.
The total momentum of the system doesn't change. In this case, it refers to the momentum of the toy truck plus the momentum of the toy car.
In an isolated system (where no external forces are acting), the total momentum of the system remains constant before and after the collision. This is known as the law of conservation of momentum.
The sum of the momentum of the two toys before the collision will be the same as the momentum of the two toys after the collision except for some losses due to heat dissipation and frictional losses.
yes the momentum of it is the same because P initial = P final ALWAYS!
Total momentum
The total momentum of the system (toy truck + toy car) is the same before and after the collision, as long as no external forces are present. This is known as the principle of conservation of momentum.
Momentum defined as p=mv.. The momentum of the truck depends on its velocity
Their combined momentum before the collision is (1000 kg * 9 m/s) + (0) = 9000 kg·m/s east. Since the vehicles move off together, their combined momentum after the collision is equal to the momentum before the collision. The total mass after collision is 3000 kg. Therefore, their speed after the collision would be 9000 kg·m/s ÷ 3000 kg = 3 m/s east.
The smaller vehicle will encounter the larger velocity change.
The principle that might apply here is momentum. Momentum is mass times velocity. What should be pointed out is that velocity is speed that has a direction vector. (If the car is moving ahead in a straight line it is traveling at "x" miles per hour "forward".) The car is moving forward and comes into contact with the truck. That seems to be where the question is looking. The mass of the car times its velocity is its momentum, and this represents the energy that it is carrying into the collision. This energy will have end up being distributed among the various parts and components of the car and the truck that are compressed, deformed and/or broken by the collision. The amount of damage will be proportional to the momentum. The more the momentum (the more the "forward" energy) of the car, the more compression, deformation and breakage there will be. Was everyone wearing seat belts? Are you in good hands?
In an inelastic collision, the two vehicles will stick together and move at a common velocity after the collision. The velocity after the collision can be calculated using the principle of conservation of momentum. Since the car is stationary, the final velocity after the collision will be 60/9 = 6.67 km/hr.
The truck is heavier