Divide both sides by 6: 3 - r = 0, so r = 3 satisfies the equation.
-x/6 - 8 = 0 Add 8 to both sides: -x/6 = 8 Multiply both sides by 6: -x = 48 Change the sign on both sides x = -48
the value that makes this ewuation true 5a=a is 2a
5y + 1 = 4y - 1 Subtract 4y from both sides of the equation. y + 1 = -1. Add 1 to both sides of the equation. y + 2 = 0 Subtract 2 from both sides of the equation. y = -2
First Equation ~ 3x-y=0 Second Equation ~ 5y=15Divide by five on both sides on the second equation to get y=3Substitute y=3 into the first equation to get 3x-(3)=0Add the three to both sides to cancel the three on the left to get 3x=3Divide both sides by 3 to get x=1
Divide both sides by 6: 3 - r = 0, so r = 3 satisfies the equation.
-x/6 - 8 = 0 Add 8 to both sides: -x/6 = 8 Multiply both sides by 6: -x = 48 Change the sign on both sides x = -48
To solve a two-step equation you want to isolate the variable in the equation. In this case it is X. first: 3X-24=0 +24 +24 add 24 to both sides second: 3X=24 3X=24 divide by three on both sides 3 3 solution: X=8 you can check your work by plugging in the X value so... 3x8-24=0 24-24=0 0=0 when both sides of the equation equal each other the X value is correct.
0
No. It is true if and only if x=0. Note that for x not equal to 0, we can divide both sides of the equation by x giving 2=3 which is false. Division by 0 is undefined so we must check x=0 manually and indeed, it solves the equation.
Set the equation equal to 0: 7h - 2 - 51 = 0 add -2 and -51 to both sides: 7h = 53 Divide h = 53/7
the value that makes this ewuation true 5a=a is 2a
the equation has exactly 1 real solution. 8-4x=0 -> add 4x to both sides. 8=4 -> divide both sides by 4. 2=x.
Any variable multiplied by zero equals zero, so you can multiply both sides of the equation by zero, but you just destroy any form of a solution you may have. For example: x = 5 x*0 = 5*0 0 = 0 Yup! By the way, what is x? Algebra is basically finding a missing variable or finding a relationship between many variables. Multiplying by 0 removes information that is crucial to solving for variables.
5y + 1 = 4y - 1 Subtract 4y from both sides of the equation. y + 1 = -1. Add 1 to both sides of the equation. y + 2 = 0 Subtract 2 from both sides of the equation. y = -2
First Equation ~ 3x-y=0 Second Equation ~ 5y=15Divide by five on both sides on the second equation to get y=3Substitute y=3 into the first equation to get 3x-(3)=0Add the three to both sides to cancel the three on the left to get 3x=3Divide both sides by 3 to get x=1
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.