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How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
What is the center of the circle given by the equation ((x plus 5)2 (y-8)21?
The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
How do you find the center and radius with an equation not in standard form?
By using Cartesian equations for circles on the Cartesian plane
What is the standard form of an equation were the poin 3-6 is on a circle whose orgin is the center?
32+62=45 so the standard form is x2+y2=45
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
What is the center of the circle given by the equation ((x plus 5)2 (y-8)21?
The equation you provided appears to be incorrectly formatted. However, if you meant to write the standard form of a circle's equation, which is ((x - h)^2 + (y - k)^2 = r^2), then the center of the circle is given by the point ((h, k)). For the specific equation you intended, please clarify the format, and I can help identify the center accordingly.
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
What is h in the standard form equation of a circle if the center is at h v and the radius is r?
(x - h)2 + (y - v)2 = r2
What is the standard form of the equation of a circle with center (2 3) and radius 4 units?
(x-2)^2 +(y-3)^2 = 16
What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
What is the standard form of the equation of a circle with its center at (2 -3) and passing through the point (-2 0)?
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
