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Possibly (-7, 5) but limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
What else can I help you with?
What is the center of the circle given by the equation (x - 3)2 plus (y - 9)2 16?
If you mean: (x-3)^2 +(y-9)^2 = 16 then the center of the circle is at (3, 9)
Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16?
(-7,5)
What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
What is the equation of the circle with the center at the origin and r 4?
x2 + y2 = 16
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
Where is the center of the circle given by the equation (x plus 7)2 plus (y - 5)2 16 Enter your answer as an ordered pair.?
The center of the circle is at (-7, 5)
What is the center of the circle given by the equation (x - 3)2 plus (y - 9)2 16?
If you mean: (x-3)^2 +(y-9)^2 = 16 then the center of the circle is at (3, 9)
Where is the center of the circle given by the equation x plus 7 2 plus y - 5 2 equals 16?
(-7,5)
What is the center of the circle given by the equation (x - 3)2 (y - 9)2 16?
Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.
What is the equation of the circle with the center at the origin and r 4?
x2 + y2 = 16
What are the coordinates of the center of the circle described by the equation x2 y 52 16?
The equation provided appears to have a typographical error, as it should likely be in the form of a standard circle equation. If you meant (x^2 + y^2 = 16), the center of the circle is at the coordinates (0, 0). If this is not the correct interpretation, please clarify the equation for an accurate response.
I have a maths question i dont get please help me!"Describe fully the graph which has the equation x² + y² = 16."?
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
Where is the center of the circle given by the equation x plus 7 2 plus y 5 2 equals 16 Enter your answer as an ordered pair?
(x+7)2+(y+5)2 = 16 Centre of circle: (-7, -5) Radius: 4
What is the center and radius of the circle with equation (x - 5)2 (y 3)2 16?
center 5,-3 radius 4
What is the center and radius of a circle described by the equation x2 y2 8x 4y 16 0?
To find the center and radius of the circle given by the equation (x^2 + y^2 - 8x - 4y - 16 = 0), we first rewrite it in standard form. Completing the square for both (x) and (y) gives us ((x - 4)^2 + (y - 2)^2 = 36). Thus, the center of the circle is at ((4, 2)) and the radius is (6) (since (r = \sqrt{36})).
What is the equation of a circle with center (-35)and radius 4?
It is: (x+3)^2 + (y-5)^2 = 16
What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
