It would be a straight line without any ends, going from lower left to upper right
at 45 degrees. It would cross the y-axis 3 units below the origin, and it would
cross the x-axis 3 units to the right of the origin. You can use those two points
to draw the line, and then keep going because the graph of the equation has
no ends.
if this is an x,y plot, it would be a vertical line at x = -3
Yes, x = -3 would represent a vertical line at abscissa -3, parallel to the y-axis.
3
So this would be a verticle line which passes through the point at -3.
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
if this is an x,y plot, it would be a vertical line at x = -3
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
Yes, x = -3 would represent a vertical line at abscissa -3, parallel to the y-axis.
Upwards.
down
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
3
So this would be a verticle line which passes through the point at -3.
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
6
The is a straight line parallel to the y-axis with an x intercept at -3.