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I assume that is a straight line between point (0, 0) and point (3, 1):
The equation of any line is given by:
y - yo = m(x - xo)
where m is the gradient given by:
m = (y1 - yo)/(x1 - x0)
Thus, line is:
y - 0 = (1 - 0)/(3 - 0)(x - 0)
⇒ y = 1/3 x
or 3y = x
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What is the equation of a line that passes through the point 0 2 and is perpendicular to a line with a slope of 3?
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
What is the equation of (0 -1) (1 1) (2 3)?
The slope of the line is 2 and its equation is y = 2x-1
What is the equation of the line that contains the points (3 -6) and (-3 0)?
Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
A line passes through the points 0-1 and 2 3 What is the equation for the line?
Suppose the equation of the line is y = mx + c. (0,-1) is on this line so -1 = m*0 + c ie -1 = c so y = mx - 1 Also, (2,3) is on the line so 3 = m*2 - 1 or 2m = 4 so m = 2 So the equation of the line is y = 2x - 1
What is the equation of a line that passes through the point 0 2 and is perpendicular to a line with a slope of 3?
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
What is the equation of (0 -1) (1 1) (2 3)?
The slope of the line is 2 and its equation is y = 2x-1
What is the equation of the line that contains the points (3 -6) and (-3 0)?
Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
What is The graph of a line passes through the points (0 -2) and (6 0). What is the equation of the line?
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
If the equation of a line passes through the points (1, 3) and (0, 0), which form would be used to write the equation of the line?
Slope-intercept form
What is an equation for line (-12 3) and (00)?
If you mean points of (-12, 3) and (0, 0) then the equation is y = -1/4x or 4y = -x
What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
A line passes through the points 0-1 and 2 3 What is the equation for the line?
Suppose the equation of the line is y = mx + c. (0,-1) is on this line so -1 = m*0 + c ie -1 = c so y = mx - 1 Also, (2,3) is on the line so 3 = m*2 - 1 or 2m = 4 so m = 2 So the equation of the line is y = 2x - 1
What is the equation of the line from the origin to the middle of the line with endpoints at 3 2 and 5 -1 on the Cartesian plane?
Endpoints: (3, 2) and (5, -1) Midpoint: (4, 0.5) Slope of line from (0, 0) to (4, 0.5) = 1/8 Equation of line: y = 1/8x
What is the equation of a line that passes through points (0 -1) and (2 3)?
As Slope=m=3-(-1)/2-0=2 So equation is y-(-1)=2×(x-0) y+1=2x 2x-y-1=0
Graph 3x-y equals 3?
0
What is the equation of the line that passes through the point 0 and 3 and is perpendicular to the line y equals 2x plus 3?
y-3 = -1/2(x-0) y = -1/2x+3
