y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The question refers to "this equation". In such circumstances would it be too much to expect that you make sure that there is some equation that is following?
None of them, since there is nothing following.
There is more than one "standard form". If the equation is not already solved for "y", solve it for "y". In that case, you'll get an equation of the following form (known as "slope-intercept form"): y = mx + b Where "m" is the slope of the line, and "b" is the y-intercept (the point where the line intercepts the y-axis).
2VdV + 2PdP + 3T2dT (this is an expression, not an equation because there is no equals sign)
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
There are no "following" data!
y = b
y=b
The question refers to "this equation". In such circumstances would it be too much to expect that you make sure that there is some equation that is following?
The second element in a chemical equation is typically the element to the right in the equation following the first element. The second element will combine with the first element to form a compound or molecule.
I need step by step on my graphic calculator on how to write an equation
None of them, since there is nothing following.
y = mx + cm = slopec = constantif we convert above equation in following form,y = 1.25x-2thus slope is 1.25
There is more than one "standard form". If the equation is not already solved for "y", solve it for "y". In that case, you'll get an equation of the following form (known as "slope-intercept form"): y = mx + b Where "m" is the slope of the line, and "b" is the y-intercept (the point where the line intercepts the y-axis).