There are none of them on the list you provided with your question.
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
The point-slope form of a line is given by the equation ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. Given a slope of -3 and the point (10, -1), we can substitute these values into the formula: ( y - (-1) = -3(x - 10) ). This simplifies to ( y + 1 = -3(x - 10) ), or ( y + 1 = -3x + 30 ). Thus, the point-slope form is ( y + 1 = -3(x - 10) ).
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
y=1.33x-4.68
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean point of (1, 4) and slope of -10 then y = -10x+14
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
It is: y = -10x+14
It is: y = -10x+14
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
Need point slope form. Y = mX + c 4X + 2Y = 10 2Y = - 4X + 10 Y = - 2X + 5 ========= slope(m) = - 2 -------------------
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Check whether the slope between point #1 and point #2 is the same as the slope between point #2 and point #3. If it is, then they are collinear.
The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.The slope of a line and the coordinates of a point on the line.
y=1.33x-4.68