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Which of these ordered pairs are solutions to the equation 5x 1?
None of them.None of them.None of them.None of them.
A quadratic equation can't have one imaginary solution?
That's true. Complex and pure-imaginary solutions come in 'conjugate' pairs.
How do you find 3 different ordered pairs that are solutions of the equation?
Select any three values of x in the domain of the equation. Solve the equation at these three points for the other variable, y. Then each (x, y) will be an ordered pair that is a solution of the equation.
Which 2 order pairs are solutions of y x 5?
Which 2 order pairs are solutions of y x + 5
How can you determine whether a polynomial equation has imaginary solutions?
To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
