If you mean y = -2x-6 then y intersect the graph at (0, -6)
Start with the first equation: 8=2x-6 so 14=2x so x=7 Now insert the answer for x into the second equation: So y=2(7)-6 so y=14-6 so y=8 So at a certain point x=7 and y=8 so a coordinate would be (7,8)
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
No. If x = -2, then y = -(2x) -(+6) = -2*(-2) - 6 = +4 - 6 = -2
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If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.
If you mean y = -2x-6 then y intersect the graph at (0, -6)
Start with the first equation: 8=2x-6 so 14=2x so x=7 Now insert the answer for x into the second equation: So y=2(7)-6 so y=14-6 so y=8 So at a certain point x=7 and y=8 so a coordinate would be (7,8)
If you mean: y = x^2+4x+3 and y = 2x+6 Then the solution is: x = 1 or x = -3
y-1 = 2(x-3) y-1 = 2x-6 y = 2x-6+1 y = 2x-5
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y=2x-4 y=2x-5 y=1 1=2x-4 -2x = -5 x=2/5 the solution is (x,y) = (2/5,1)
No. If x = -2, then y = -(2x) -(+6) = -2*(-2) - 6 = +4 - 6 = -2
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Y = -2X + 6 The line has a slope of -2 and passes through the point Y=6 on the Y-axis. -- From the point Y=6 on the Y-axis, move 1 to the right and 2 down. This brings you to the point (1, 4). Mark the point. -- Place your ruler so that the point Y=6 and the point (1, 4) are both along the ruler's edge, and draw the line.
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