You do not have to plot it first but it is a point whose location is sometimes easy to find.
by eating a bana and yes
13
The easy way is to plot the x- and y-intercept points and draw the lines that passes through those two points. If y = 0, then we have 3x = -2and x = -2/3. So the x-intercept point is (-2/3, 0). If x = 0, then we have -y = -2and y = 2. So the y-intercept point is (0, 2). Plot the points and draw the line.
In the case that you are using Slope-Intercept Form, no, you only plot two points: the y-intercept and one other point. If you don't use Slope-Intercept Form, then you have to use three points.
To graph equations, first, rearrange the equation into a format like (y = mx + b) for linear equations, where (m) is the slope and (b) is the y-intercept. Plot the y-intercept on the graph, then use the slope to find another point. For nonlinear equations, calculate several values of (x) to find corresponding (y) values, then plot these points and connect them to form the curve. Finally, label your axes and provide a title for clarity.
Plot the y-axis, which is the b in the y=mx+b in the slope intercept equation. Then, you put your slope and plot the line.
To determine the maximum velocity (Vmax) from a Lineweaver-Burk plot, you can find the y-intercept of the plot. Vmax is equal to the reciprocal of the y-intercept.
by eating a bana and yes
13
To graph the equation y-x=3, first rearrange it in slope-intercept form by isolating y: y=x+3. This equation represents a line with a slope of 1 and y-intercept of 3. You can plot the y-intercept at (0,3) then use the slope to find another point and draw a straight line connecting the two points.
Measure the distance between the point where the line intercepts the Y axis and the origin
The easy way is to plot the x- and y-intercept points and draw the lines that passes through those two points. If y = 0, then we have 3x = -2and x = -2/3. So the x-intercept point is (-2/3, 0). If x = 0, then we have -y = -2and y = 2. So the y-intercept point is (0, 2). Plot the points and draw the line.
In the case that you are using Slope-Intercept Form, no, you only plot two points: the y-intercept and one other point. If you don't use Slope-Intercept Form, then you have to use three points.
To find the Y-intercept, plug 0 in for X, so you have 0+Y=-3, or Y=-3. Therefore, your Y-intercept is at the point (0,-3). You do the same thing to find the X-intercept, only reversed. X+0=-3, so X=-3. This intercept is at (-3,0).
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
To graph equations, first, rearrange the equation into a format like (y = mx + b) for linear equations, where (m) is the slope and (b) is the y-intercept. Plot the y-intercept on the graph, then use the slope to find another point. For nonlinear equations, calculate several values of (x) to find corresponding (y) values, then plot these points and connect them to form the curve. Finally, label your axes and provide a title for clarity.
You have to put a line of best fit onto the graph and find where that line crosses the y-axis.