To find the Y-intercept, plug 0 in for X, so you have 0+Y=-3, or Y=-3. Therefore, your Y-intercept is at the point (0,-3). You do the same thing to find the X-intercept, only reversed. X+0=-3, so X=-3. This intercept is at (-3,0).
-1
I think its line plot
ex = x3 This has two solutions: x = 4.5364... and x = 1.85718... Plot the graph of each and you can see the intersections.
x2 + y - 49 = 0y = -x2 + 49First, plot the graph of y = -x2, with a vertex (0, 0), then translate it 49 units up. The vertex becomes (0, 49), which is a maximum point (the parabola opens downward).Or make a table to obtain several corresponding y-values for x = -3, -2, -1, 0, 1, 2, 3. Plot the points (x, y), and draw the graph of y = -x + 49.
First note that this not the graph of y = |cot(x)|.The equivalent equations for |y| = cot(x) or cot(x) = |y| arecot(x) = -y or cot(x) = +ySo plot y = cot x and then reflect all the points in the x-axis.
No; it means draw the curve.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
You plot the equation as a graph. Every one of the infinitely many points on the graph is a solution.
-2.25
Plot the solution of the equation for various variables in the equation
y=x+4 To graph this, you need to find the y-intercept in the equation which is 4. Plot that on the graph by going up 4 from the origin (0,0). Next, go right one, up one and plot. Then, right one, up one again.
Graph it (the equation).
X = 4 is a vertical line, 4 units to the right of the y-axis.
To draw the graph of an equation, start by identifying the type of equation (linear, quadratic, etc.) and determining its key features, such as intercepts and slope. Plot points by substituting values for the variable(s) to find corresponding outputs. Connect the plotted points smoothly, following the shape dictated by the equation type. Finally, label the axes and any important points to enhance clarity.
graph
graph
y=-x Draw a straight line with slope -1 passing through (0,0). Or, plot (x,y) coordinates that satisfy the equation, and connect the dots.