Question doesn't really make sense unless you mean x1=x and you want to know what x is. And if so, then x is any number. Because any number multiplied by 1 is unchanged. So that makes it:
x=x
Which is very much like saying 1=1 or "Apples are Apples". Sure it's true, but there's not much to do with it beyond that.
B - B1 = M ( A - A1)Where (Y - Y1) / (X - X1) = MThis will give you the gradient of a line.
Long story short- x2 / x = x , x3 / x = x2 , so x1 /x = x0 , and any whole number besides zero divided by itself is equal to one, therefore x0 is equal to one.
x*x1/2= x3/2 Derivative = 3/2 * x1/2
It is x1 which is x.
Here are some examples. x1/2 = square root of x; x1/3 = cubic root of x; in general, x1/n = nth root of x. Also, x2/3 = the square of the cubic root of x, or equivalently, the cubic root of the square of x.
sqr.rtx/x= sqrt.x*sqr.rtx/sqr.rtx=x/x*sqrt.x=1/sqrt.x. x1/2 = x1/2 * x1/2 = x = 1 (x1/2) /x= 1/x1/2
B - B1 = M ( A - A1)Where (Y - Y1) / (X - X1) = MThis will give you the gradient of a line.
it equals x1 it equals x1
x1 = x
Long story short- x2 / x = x , x3 / x = x2 , so x1 /x = x0 , and any whole number besides zero divided by itself is equal to one, therefore x0 is equal to one.
x*x1/2= x3/2 Derivative = 3/2 * x1/2
The proof of the Newton-Raphson iterative equation involves using calculus to show that the method converges to the root of a function when certain conditions are met. By using Taylor series expansion and iterating the equation, it can be shown that the method approaches the root quadratically, making it a fast and efficient algorithm for finding roots.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
It is x1 which is x.
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
Here are some examples. x1/2 = square root of x; x1/3 = cubic root of x; in general, x1/n = nth root of x. Also, x2/3 = the square of the cubic root of x, or equivalently, the cubic root of the square of x.