In order for your integration to be complete it has to represent the fact that it has infinite solutions, or else there's a possibility to have fallacies in the proofs you write. In other words, by neglecting the constant in your answer, it may be possible to extrapolate erroneous proofs from your incomplete answer, like 1 + 1 = 3, for example.
A little more practically, the constants of integration are great for bookkeeping when dealing with multiple integrals.
For example, here's the result from a simple triple integral without adding in the constants of integration:
∫∫∫ (xyz) dxdydz = ∫∫ (yzx2/2) dydz = ∫ (x2y2z/4) dz = x2y2z2/8
Whereas, with the constants added in you get this result:
∫∫∫ (xyz) dxdydz = ∫∫ (yzx2/2 + C) dydz = ∫ (x2y2z/4 + Cy + D) dz =
x2y2z2/8 + Cyz + Dz + E, where C, D, and E are the constants of integration.
This result has a term with both yz and z in it that we had initially missed, which could have had crucial applications to whatever this function is describing.
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It is cosh(x) + c where c is a constant of integration.
Assuming integration is with respect to a variable, x, the answer is 34x + c where c is the constant of integration.
The solution to a differential equation requires integration. With any integration, there is a constant of integration. This constant can only be found by using additional conditions: initial or boundary.
The indefinite integral is the anti-derivative - so the question is, "What function has this given function as a derivative". And if you add a constant to a function, the derivative of the function doesn't change. Thus, for example, if the derivative is y' = 2x, the original function might be y = x squared. However, any function of the form y = x squared + c (for any constant c) also has the SAME derivative (2x in this case). Therefore, to completely specify all possible solutions, this constant should be added.
∫ ax dx = ax/ln(a) + C C is the constant of integration.