Because without an equality sign it can not be considered to be an equation and therefore has no solution.
To determine if ( x = 9 ) is a solution of the equation ( x + 6(x - 4) = 0 ), substitute ( 9 ) for ( x ): [ 9 + 6(9 - 4) = 9 + 6(5) = 9 + 30 = 39 \neq 0. ] Since the left side does not equal zero, ( x = 9 ) is not a solution of the equation.
Is (7, 9) a solution to the equation y = x?
To determine if ( x^3 ) is a solution of the equation ( 3x - 54x = 0 ), we first simplify the equation. The left side simplifies to ( -51x = 0 ), which implies ( x = 0 ) is the only solution. Since ( x^3 ) is not equal to ( 0 ) for any ( x ) other than ( 0 ), ( x^3 ) is not a solution to the equation.
x - 9 is an expression, neither an equation not an inequality. An expression cannot have a solution.
Only a linear equation in one variable x , which is an equation of the form ax + b = 0, (where a is different than 0), has only one solution. The solution is: x = -b/a
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
Is (7, 9) a solution to the equation y = x?
Of course, x-1=8 is a solution. Any equation which results with the variable value as 9 is ur answer. For eg: x = 9 / x-9 = 0 1 - x = -8 / x-1 = 8 x-2 = 7 / 2-x = -7 Any, any such equation will be your answer(correct answer). Enjoy
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x - 9 is an expression, neither an equation not an inequality. An expression cannot have a solution.
Only a linear equation in one variable x , which is an equation of the form ax + b = 0, (where a is different than 0), has only one solution. The solution is: x = -b/a
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.
How about x+4 = 0 ?
X+9=17;8
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
It is a linear equation in x. The equation has the solution x = 0.
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.