Equation of line:
y - yo = m (x - xo)
y - 6 = -2 (x - 3)
y - 6 = -2x +6
y + 2x = 12
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
The equation is [ y = 3 ].
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
As a straight line equation: y = -3x+18 in slope intercept form
It is: y-7 = 2(x-3) => y = 2x+1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y = 2x + 1.
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The equation is [ y = 3 ].
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
Choose the equation of the line that contains the points (1, -1) and (2, -2).
As a straight line equation: y = -3x+18 in slope intercept form