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Assuming the expression you want to solve is: x^2 + 10x + 25 = 81
Subtract both sides by 81: x^2 + 10x - 56=0
First, check for factors of 56 whose difference is 10: 2 and 28, no, 4 and 14, yes.
So factor the expression as: (x+14)(x-4)=0
Thus the solutions to the expression are either x=4 or x=-14.
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How do you solve x squared equals 10x minus 25?
Rearrange: x2 - 10x + 25 = 0ie (x - 5)(x - 5) = 0x = 5Check: x2 = 25; 10x - 25 = 50 - 25 = 25. Job done
10x-25 equals 4x plus 5 what does x equal?
10x - 25 = 4x + 510x - 4x = 25 + 56x = 30x = 5
What is the answer to 10x plus 7 equals 5x plus 32?
10x+7 = 5x+32 10x-5x = 32-7 5x = 25 x = 5
What are the solutions to x squared plus 10x plus 25 equals 8?
This simplifies to x2 + 10x + 17 = 0 which has no solution in integers. Quadratic formula gives roots as -2.17 and -7.83 to the nearest hundredth. If the original equation had been "equals 0" rather than "equals 8", there would have been only one root: x = -5
What is the area of a square with a side whose length equals x plus 5?
x2+10x+25
