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x = 6.5y = 16.9
It is the point of intersection of its three main diagonals.
The radius of a circle is half the length of the diameter. Scroll down to related links to find more about the diameter and the radius.
highest point is 209 m (at intersection of Steeles Ave West and Keele St) http://www.toronto.ca/toronto_facts/geography.htm
The Radius of the Star is 10 KM. Now we need to find the diameter. Circumference equals pi times the Diameter. That is twice the Radius, which is 20. Now we need to get the Diameter. We multiply the diameter by pi. 20 times 3.1416. 20 * 3.1416 = 62.838. Now we multiply the circumference in kilometers by the speed. 62.832 * 642 = 40,338. Now we take the speed of light, 299,997 per second and divide it into the speed of a point on the equator of our star going 40,338 kilometers per second. 40338 / 299997 = 0.1345
1,6
The intersection is (-2, 6)
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
2
The coordinates of the point of intersection is (1,1).
3
-- You do not need the 'square'. You only need the 'pi' and the diameter. -- The circumference of a circle is (pi) x (diameter). -- Is it really necessary to go further and point out that the length of a semicircle is 1/2 of that ?
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
Infinitely many. Each point on the circumference of a semicircle can be one end of a diameter and there are infinitely many points in a line segment of any length.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Probably not. But there is not enough information in the question to be certain.
They intersect at the point of: (-3/2, 11/4)