15rr+2rs-ss
axx+bx+c
a=15
b=2
c=-1
Multiply a and c:
15*-1=-15
Find multiples of ac that add up to b (d,e [ie de=ac, d+e=b]):
15=3*5
-15=-3*5, -5*3
Rewrite axx+bx+c into axx+dx+ex+c:
15rr+2rs-ss
15rr-3rs+5rs-ss
Factor sets of terms (ie axx+dx, and ex+c):
15rr-3rs+5rs-ss
3r(5r-s)+s(5r+s)
Combine like terms:
3r(5r-s)+s(5r+s)
(5r-s)(3r+s)
The other factor is 1.
12n2 plus 8n?
(a + 2b)(c + 2d)
6x(3x2 - x + 4)
(x + 4)(x + 8)
5m
The other factor is 1.
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
factor the trinomial 16x^2+24x+9
You can't factor it
That does not factor neatly.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
Not factorable
1
No
The only factor is 2. 2*(t3 + 2t2 + 4x)