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Maxine
Professor
BlakeSome of these you can just look at and tell. First manipulate algebraically to,
X^2 = 7X
X^2 - 7X = 0
You can immediately see that only two integers can possible be factors here.
one must be 0
0^2 - 7(0) = 0
0 = 0
and the linear value gives you the other integer
7^2 - 7(7) = 0
49 - 49 = 0
0 = 0
these are all a type
X = 0
X = 7
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How factor the following trinomials completely which is 4x2-24x plus 32?
Dividing all terms by 4 gives: x2-6x+8 = (x-2)(x-4) when factored
How do you factor polynomials?
A few examples..** First, taking out a common factor:1:x3 + 3xx(x2 + 3) -This is factored because you have taken an "x" away from both terms... to put it back into its original form just multiply the "x" by x2 and 3.2:6x2 + 16x + 82(3x2 + 8x + 4) -All of the numbers were divisible by 2 so you can take 2 out of all of the terms.** Factoring a Difference of Squares:x2 - 16 = (x)2 - 42 = (x - 4)(x + 4).** An 'easy' trinomial (the coefficient of x is 1):x2 + 5x + 6 = (x + 3)(x + 2). -Notice that 2+3=5 and (2)(3) =6.** A 'hard' trinomial (the coefficient of x2 is not 1):8x2 - 2x - 21 = (2x + 3)(4x - 7). -There are several ways of organizing a trial and error process to factor a case like this.** Factoring by grouping (Check for this when there are 4 terms.)6x3 - 2x2 + 15x - 5 = 2x2(3x - 1) + 5(3x - 1) = (2x2 + 5)(3x - 1).
What is the polynomial and degree of 7x3 6x2 -2?
The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
What factor of 6x2 plus x1 - 11 in zeros of polynomial function?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
What are the factors of 6x squared plus 7x minus 3?
We are looking for a factorization like 6x² + 7x - 5 = (_x + _)(_x - _) where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By trial and error, we arrive at the factorization 6x² + 7x - 5 = (2x - 1)(3x + 5).
