The GCF is 2. The LCF is 1. The difference is 1.
90 - 2 = 88 2 - 90 = -88
find the difference between any 2 numbers which pairs have a difference of 123
The term common factoring is relating to what is common among two or more things. This same technique is used in math. In math some problems require the common factor to be found. A common factor of the numbers 4 and 8 would be the number 2.
8 is.
-8
6
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
-8
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
-8
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...
To find the sum of all even numbers from 2 through 200, we can use the formula for the sum of an arithmetic series. Since the sequence is an arithmetic sequence with a common difference of 2, we can calculate the number of terms using the formula ((last term - first term) / common difference) + 1. In this case, the first term is 2, the last term is 200, and the common difference is 2. Plugging these values into the formula gives us ((200 - 2) / 2) + 1 = 100. The sum of an arithmetic series is given by the formula n/2 * (first term + last term), so the sum of all even numbers from 2 through 200 is 100/2 * (2 + 200) = 10100.
n = 1, 2n = 2 n = 2, 2n = 4 n = 3, 2n = 6 2, 4, 6, ..., 2n where n = 1, 2, 3, ... This is an arithmetic sequence, where the first term is 2 and the common difference is 2.
Since there are no graphs following, the answer is none of them.
sum = 1/2 x number_of_terms x (first + last) number_of_terms = (last - first) ÷ difference + 1 = (25 - 0.5) ÷ 3.5 + 1 = 8 ⇒ sum = 1/2 x 8 x (0.5 + 25) = 102
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.