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In this geometric sequence what is the common ratio 104 -52 26 -13 ...?
To find the common ratio in the geometric sequence 104, -52, 26, -13, we divide any term by the previous term. For example, dividing the second term (-52) by the first term (104) gives -52 / 104 = -1/2. Similarly, -13 / 26 also results in -1/2. Therefore, the common ratio is -1/2.
What is the difference between greatest common factor and least common factor using the numbers 6 and 8?
The GCF is 2. The LCF is 1. The difference is 1.
What is the difference between the greatest common factor and the least common multiple of 10 and 18?
90 - 2 = 88 2 - 90 = -88
What do Lonnie Bromer and Stefan Grondowski have in common?
find the difference between any 2 numbers which pairs have a difference of 123
What is the mathematical formulation for 100 125 150 175 200 225 250 275 300?
The given sequence can be expressed mathematically as an arithmetic sequence, where the first term ( a = 100 ) and the common difference ( d = 25 ). The ( n )-th term of the sequence can be represented by the formula ( a_n = 100 + (n-1) \times 25 ). Thus, the terms can be calculated for ( n = 1, 2, 3, \ldots, 9 ).
What is the tenth term if the first term is -10 and the common difference is -2?
-8
If a equals 4 and d equals -2 what is the first four terms of the arithmetic sequence?
6
What is the nth term of 3 6 11 18 27?
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.
What are the first ten terms of a sequence whose first term is -10 and whose common difference is -2.?
-8
What are the first ten sequences whose first term is -10 and whose common difference is -2?
-8
What is the nth term of an AP?
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...
What is the 10 term of the sequence 3 5 7 9?
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
What is the formula of arithmetic series?
The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
What is the nth term 6 8 10 12?
The given sequence 6, 8, 10, 12 is an arithmetic sequence with a common difference of 2 between each term. To find the nth term of an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1) is 6 and the common difference (d) is 2. So, the nth term (a_n = 6 + (n-1)2 = 2n + 4).
What is the formula for the nth term of this sequence 14 22 30 38 46?
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
What is the nth term of the sequence 2 4 6 8?
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
What is the sum of all the even numbers from 2 through 200?
To find the sum of all even numbers from 2 through 200, we can use the formula for the sum of an arithmetic series. Since the sequence is an arithmetic sequence with a common difference of 2, we can calculate the number of terms using the formula ((last term - first term) / common difference) + 1. In this case, the first term is 2, the last term is 200, and the common difference is 2. Plugging these values into the formula gives us ((200 - 2) / 2) + 1 = 100. The sum of an arithmetic series is given by the formula n/2 * (first term + last term), so the sum of all even numbers from 2 through 200 is 100/2 * (2 + 200) = 10100.
