The GCF of 4 and 6 is 2.
(n - 4)(2n + 3)
Phil!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!he has a shirt covered in blood in his bag so put 2n2 2gether!!!!!!!!!!!!!!!!!!!!! <3
factor I (fibrinogen), factor II (prothrombin), factor III (tissue thromboplastin), factor IV (calcium), factor V (proaccelerin), factor VI (no longer considered active in hemostasis), factor VII (factor-vii), factor VIII (antihemophilicfactor), factor IX (plasma thromboplastincomponent; Christmas factor), factor X (stuart-factor-stuart-prower-factor), factor XI (plasma thromboplastinantecedent), factor XII (factor-xii), factor XIII (fibrin stabilizing factor).
factor pair = 36,1 factor pair = 18,2 factor pair = 12,3 factor pair = 9,4 factor pair = 6,6
(2n - 3)(n - 6)
2(n2+3n-54) 2(n+9)(n-6)
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)
Divide all the terms by 4:- 2n2-9n+10 = (2n-5)(n-2) when factored
2NH4NO3->2N2+O2+4H2O
The GCF of 4 and 6 is 2.
n * 2n = 2n2
(n - 4)(2n + 3)
yes
M5h 2n2
2n2 / n = 2n
2 eyes on the road and 2 hands on the wheel