Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
It is not possible to be certain about it being the "greatest" common factor, because 2 or 3 or 6 may be a factor of x, but the general solution for practical purposes is: 11x = 11*x and -66 = 11*(-1)*2*3 so [g]cf is 11.
x(6x - 11)
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
4x2-11x-20=(x-4)(4x+5) 4x2-11x-20=4x2+ax+bx-20ab = 4*-20 = -80a+b = -11a = -16, b = 54x2-11x-20=4x2-16x+5x-204x2-16x+5x-20=4x(x-4)+5(x-4)4x(x-4)+5(x-4)=(x-4)(4x+5)Factorised, 4x2-11x-20=(x-4)(4x+5)
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
By using the quadratic equation formula: (4x+1)(x-3) = 0
If that's - 11x - 20, the answer is (4x + 5)(x - 4). If that's + 11x + 20, it gets ugly in a hurry.
Solution: x = 1/4 and x = -3.
4x2-11X=7 ARRANGE IN STANDARD FORM
(4x + 3)(x - 1)
4x2(4x3 + 3)
(2x + 3)(2x - 1)