I hope you mean x3+2x2-9x+18.
Treat the equation like two equations: x3+2x2 and 9x+18.
Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2).
Now, the whole equation. x2(x+2)-9(x+2).
Factor out (x+2), so (x+2)(x2-9).
(x2-9) factors into (x+3)(x-3).
So, (x+2)(x+3)(x-3) is the complete factorization.
Hope this helps.
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-9(x + 8)
7
3x + 1)(3x - 4)
3x2 - 9x - 912 = 3(x2 - 3x - 304) = 3(x - 19)(x + 16).
This polynomial is irreducible; it cannot be factored.