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Q: How do you factor 9x squared-18?

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3x2 + 9x 3x(x + 3) -------------

You take out the common factor, x. x2 - 9x = x(x - 9)

5x2 + 9x + 13 has no real factors.

If that's -49, there is a formula for the "difference of squares." In this case, the answer is (9x + 7)(9x - 7)

The GCF is 3x.

Related questions

factor out a 3x 3x(x-3)=3x2-9x

You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.

x2-9x = x(x-9)

The GCF of 6x and 9x is 3x

3x2 + 9x 3x(x + 3) -------------

If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2

102 +9x +4 = 9x + 106, which is in its simplest form.

If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2

If that's + 18x + 1, the answer is (9x + 1)(9x + 1) or (9x + 1)2

Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6) Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6)

You take out the common factor, x. x2 - 9x = x(x - 9)

you can't

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