I hope you mean x3+2x2-9x+18.
Treat the equation like two equations: x3+2x2 and 9x+18.
Factor out x2 from the first equation, so x2(x+2). Factor out 9 from the second equation, so 9(x+2).
Now, the whole equation. x2(x+2)-9(x+2).
Factor out (x+2), so (x+2)(x2-9).
(x2-9) factors into (x+3)(x-3).
So, (x+2)(x+3)(x-3) is the complete factorization.
Hope this helps.
-9(x + 8)
7
3x + 1)(3x - 4)
3x2 - 9x - 912 = 3(x2 - 3x - 304) = 3(x - 19)(x + 16).
This polynomial is irreducible; it cannot be factored.
factor out a 3x 3x(x-3)=3x2-9x
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
x2-9x = x(x-9)
If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2
If that's + 49y2, the answer is (9x - 7y)(9x - 7y) or (9x - 7y)2
102 +9x +4 = 9x + 106, which is in its simplest form.
If that's + 18x + 1, the answer is (9x + 1)(9x + 1) or (9x + 1)2
Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6) Asuming you ment The Factor of x^2+9x+18 the answer is (x+3)(x+6)
The GCF of 6x and 9x is 3x
you can't
65
9x+39