x2+2x-63 = (x-7)(x+9) when factored
The difference of two squares a2 - b2 factors to (a - b)(a + b)
(5x - 3)(x + 8)
First you express the numbers as their prime factors: 3y = 3, y y2 = y, y Next you identify any common prime factors. In this case both numbers have y as a prime factor. Finally you multiply the numbers and divide by the HCF: 3y(y2)/y = 3y2 and thus the LCM is 3y2
(2x - 9)(2x - 9) or (2x - 9)2
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
4x3+10x2+2x+5= (2x+5)(2x2+1)
(2x+3)(x+3)
2x + 5 = 31 2x = 31 - 5 = 26 x = 13
(2x - 3)(x + 2)
(2x + 1)(x + 3) are the factors.
9(2x + 5)
I assume you mean factors for 4x2+10x+6.(2x+3)(2x+2).
It is an equation and the value of x is 4
2x^2 + 13 doesn't have rational factors.
x^3+x^2+2x = x(x^2+x+2)
No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)