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Can two third-degree polynomials be added to produce a second-degree polynomial?
Yes. If the coefficient of the third degree terms in one polynomial are the additive inverses (minus numbers) of the coefficient of the corresponding terms in the second polynomial. Eg: 3x3 + 2x2 + 5 and -3x3 + x - 7 add to give 2x2 + x - 2
When polynomial is a quadratic polynomial?
Whenever there are polynomials of the form aX2+bX+c=0 then this type of equation is know as a quadratic equation. to solve these we usually break b into two parts such that there product is equal to a*c and I hope you know how to factor polynomials.
Why do math problems have two answers?
Assuming that you are reffering to something like this: (x - h)(x - k) = 0 x = h, x = k This is the fundamental theorem of algebra which states that is given a polynomial (multiple terms raised to positive powers ex) x^3 + 2x + 1), then the number of solutions to that polynomial is equal to the degree (or highest exponent) in the polynomial. The factorization in the beginning was dealing with a quadratic equation - when foiled out it equals x^2 - hx - kx + hk. The highest exponent in the quadratic is two and therefore there are two solutions. You can even think back to the factorization again: if x = h then the whole equation is 0, if x = k then the whole equation is 0.
The graph of a polynomial changes direction twice and has only one root What can you say about the polynomial?
It is a polynomial of odd power - probably a cubic. It has only one real root and its other two roots are complex conjugates. It could be a polynomial of order 5, with two points of inflexion, or two pairs of complex conjugate roots. Or of order 7, etc.
This is a polynomial with two terms?
binomial
