Assuming that the equation is x2- x -12
You need two numbers that multiply to 12 whose difference is 1. (3 and 4)
The second subtraction sign says that signs will be different, the first says that the bigger number is a negative.
(x-4)(x+3) is the answer.
(x + 2)(x - 7)
x2+2x-63 = (x-7)(x+9) when factored
two factors is a binomial three factors is a trinomial four of more is a polynomial the product of any of these is just a polynomial
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
-4
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (x +6)(8 - x)
-x2 + 2x + 48 = (-x - 6)(x - 8)
2x^2
(x+6)*(x-4)
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
(x + 2)(x - 7)
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)