0
Assuming that the equation is x2- x -12
You need two numbers that multiply to 12 whose difference is 1. (3 and 4)
The second subtraction sign says that signs will be different, the first says that the bigger number is a negative.
(x-4)(x+3) is the answer.
Find two numbers that add to make -1 (the coefficient of our second term) and multiply to make 12 (the third term):
-4 * 3 = 12
-4 + 3 = -1
So negative four and three are the numbers we want. Now break the middle term down, using those two numbers:
x2 - x - 12
= x2 + 3x - 4x - 12
We now have a common factor (x + 3), that we can factor out of both the first two and the last two terms:
= x(x + 3) - 4(x + 3)
And we can group those like terms together, giving us the final answer:
= (x - 4)(x + 3)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 1201) divided by 24.
x = 1.4856436209302881
x = -1.4023102875969549
Osks
Add your answer:
Earn +20 pts
What is the factorization of the trinomial 8x2-14x-15?
(x + 2)(x - 7)
What is the Factor x2 plus 2x 63?
x2+2x-63 = (x-7)(x+9) when factored
What is a number written as a product of its factors called?
two factors is a binomial three factors is a trinomial four of more is a polynomial the product of any of these is just a polynomial
What is 2x to the power of 6 minus 128?
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
Which is a factor of the trinomial x2 x - 6?
-4
What is the factorization of this trinomial -x2 - 2x plus 48?
-x2 + 2x + 48 = (-x - 6)(x - 8)
What is the factorization of this trinomial -x2 plus 2x plus 48?
-x2 + 2x + 48 = (x +6)(8 - x)
What is the factorization of the trinomial below -x2 plus 2x plus 48?
-x2 + 2x + 48 = (-x - 6)(x - 8)
The expression below is the factorization of what trinomial Enter the trinomial in descending order Enter exponents using the caret For example you would enter x2 as x2?
2x^2
Factor the trinomial x2 plus 2x - 24?
(x+6)*(x-4)
What is the factorization of the trinomial -2x3 plus 2x2 plus 12x?
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
What is the factorization of this trinomial -2x3 - 2x2 12x?
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
What is the factorization of this trinomial -2x3 plus 2x2 plus 12x?
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
What is the factorization of the trinomial below -x2-11x plus 26?
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
How do you solve this trinomial x2-2x-63?
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
What is the factorization of the trinomial 8x2-14x-15?
(x + 2)(x - 7)
What is the factorization of this trinomial -x2 - 11x plus 26?
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
