Assuming that the equation is x2- x -12
You need two numbers that multiply to 12 whose difference is 1. (3 and 4)
The second subtraction sign says that signs will be different, the first says that the bigger number is a negative.
(x-4)(x+3) is the answer.
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Find two numbers that add to make -1 (the coefficient of our second term) and multiply to make 12 (the third term):
-4 * 3 = 12
-4 + 3 = -1
So negative four and three are the numbers we want. Now break the middle term down, using those two numbers:
x2 - x - 12
= x2 + 3x - 4x - 12
We now have a common factor (x + 3), that we can factor out of both the first two and the last two terms:
= x(x + 3) - 4(x + 3)
And we can group those like terms together, giving us the final answer:
= (x - 4)(x + 3)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 1201) divided by 24.
x = 1.4856436209302881
x = -1.4023102875969549
(x + 2)(x - 7)
x2+2x-63 = (x-7)(x+9) when factored
two factors is a binomial three factors is a trinomial four of more is a polynomial the product of any of these is just a polynomial
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)
-4
-x2 + 2x + 48 = (-x - 6)(x - 8)
-x2 + 2x + 48 = (x +6)(8 - x)
-x2 + 2x + 48 = (-x - 6)(x - 8)
2x^2
(x+6)*(x-4)
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
(x + 2)(x - 7)
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)