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Nadia Heidenreich
Wiki User
∙ 12y agoSome of these you can just look at and tell. First manipulate algebraically to,
X^2 = 7X
X^2 - 7X = 0
You can immediately see that only two integers can possible be factors here.
one must be 0
0^2 - 7(0) = 0
0 = 0
and the linear value gives you the other integer
7^2 - 7(7) = 0
49 - 49 = 0
0 = 0
these are all a type
X = 0
X = 7
Wiki User
∙ 9y agoIt is: (3x+1)(x+1) after dividing all of the terms by 2
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∙ 14y ago(3x-4)(2x+5)
x=4/3 or -5/2
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∙ 11y ago(2x - 5)(3x - 4)
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∙ 11y ago(x - 4)(3x + 5)
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∙ 11y agox2 + 6x - 27 = (x + 9)(x - 3)
Wiki User
∙ 13y ago(x+5)(x-4)
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How factor the following trinomials completely which is 4x2-24x plus 32?
Dividing all terms by 4 gives: x2-6x+8 = (x-2)(x-4) when factored
How do you factor polynomials?
A few examples..** First, taking out a common factor:1:x3 + 3xx(x2 + 3) -This is factored because you have taken an "x" away from both terms... to put it back into its original form just multiply the "x" by x2 and 3.2:6x2 + 16x + 82(3x2 + 8x + 4) -All of the numbers were divisible by 2 so you can take 2 out of all of the terms.** Factoring a Difference of Squares:x2 - 16 = (x)2 - 42 = (x - 4)(x + 4).** An 'easy' trinomial (the coefficient of x is 1):x2 + 5x + 6 = (x + 3)(x + 2). -Notice that 2+3=5 and (2)(3) =6.** A 'hard' trinomial (the coefficient of x2 is not 1):8x2 - 2x - 21 = (2x + 3)(4x - 7). -There are several ways of organizing a trial and error process to factor a case like this.** Factoring by grouping (Check for this when there are 4 terms.)6x3 - 2x2 + 15x - 5 = 2x2(3x - 1) + 5(3x - 1) = (2x2 + 5)(3x - 1).
What is the polynomial and degree of 7x3 6x2 -2?
The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
What factor of 6x2 plus x1 - 11 in zeros of polynomial function?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
What are the factors of 6x squared plus 7x minus 3?
We are looking for a factorization like 6x² + 7x - 5 = (_x + _)(_x - _) where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By trial and error, we arrive at the factorization 6x² + 7x - 5 = (2x - 1)(3x + 5).
How do you factor 6x2 plus 23x plus 7?
Simplifying 6x2 + 23x + 7 Reorder the terms: 7 + 23x + 6x2 Factor a trinomial. (7 + 2x)(1 + 3x) Final result: (7 + 2x)(1 + 3x)
6x squared plus 23x plus 20?
6x2+23x+20=0x= .7275 and -4.5634Improved Answer:-6x2+23x+20 = (3x+4)(2x+5) when factored
Is 6x2 - 4x plus 25 a trinomial?
yes.it is.
Factor 6X2 minus 23X plus 7?
(3x - 1)(2x - 7)
6x2 - 4x plus 25 is a trinomial?
Yes, 6x2 - 4x + 25 is a trinomial. This is because there are three terms (thus the name trinomial), which are "connected" by operations of addition and subtraction: 6x2, 4x, and 25.If you mean to ask how to factor this particular trinomial, please specify so in your question.
Factor the trinomial 6x2-18x plus 12?
6x2-18x+12 = (6x-6)(x-2)
Factor the trinomial 6x2 plus 14x -12?
(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order6x2 plus 13x plus 2?
6x2 + 13x + 2 = (6x + 1)(x + 2).
Which of the binomial below is a factor of this trinomial 6x2-5x-25?
6x2-5x-25 = (3x+5)(2x-5) when factored
What are the factors of this quadratic trinomial six quared plus seven x minus five?
The factors of 6x2+7x-5 are (3x+5) and (2x-1).
What is the answer to 9 plus 6x2?
9+6x2=21
Factor the trinomial 6x2 - 13x - 63?
6x2 - 13x - 63 = 6x2 + 14x - 27x - 63 = 2x(3x + 7) - 9(3x + 7) = (3x + 7)(2x - 9)
