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∙ 11y agoAcceleration is change of speed per unit of time Our car's change of speed is 60-0 = 60 mph Aceeleration is 60*3600/5.4 miles/hour squared = 40000 miles/hour squared Alternatively: 60 mph = 88 feet/sec Change of speed = 88-0 feet/sec Acceleration = 88/5.4 = 16.30 ft/sec sq.
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∙ 16y agoWiki User
∙ 14y agoTo solve this, you can use the following constant acceleration equation:
Δx = vit + 1/2at2
where Δx is the change in position, vi is the initial velocity, t is the time interval, and a is the acceleration.
To solve, simply plug in the given values.
Δx = (4.0 m/s)(5.0s) + 1/2(3.5 m/s2)(5.0s)2
Δx = 64 m
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∙ 11y agos = v(o)t + 0.5 at2 ... a = (v(f)- v(o)) /t .... v(o) = 0
v(f) = 60 miles/hr x 3600 s / 5280 ft = 450/11 ft/sec
a = (450/11)/6.8 =6.016 ft/sec2
s = 0x6.8 + 0.5x(6.016)x(6.8)2 = 139.1 feet
Wiki User
∙ 13y agoAverage speed during the 4 seconds = 1/2 (0 + 60) = 30 mph
Distance traveled = (average speed) x (time) =
(30 mi/hr) x (4 seconds) x (5,280 ft/mi)/(3,600 sec/hr) = 176 feet
Wiki User
∙ 15y agoThat's about 35 mph. That's pretty poor. Any decent car can to 60mph in about 9 or 10 seconds.
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∙ 15y ago8
Acceleration is equal to half the sum of initial and final velocities at the midpoint of the motion when the acceleration is constant. This occurs when the object has undergone half of the acceleration time and traveled half of the distance between initial and final velocities.
The distance traveled in meters can be calculated using the equation: distance = (velocity^2) / (2 * acceleration). The acceleration should be converted from g to m/s^2 by multiplying by 9.81 m/s^2 per g. Plugging in the values, the distance traveled would be approximately 32.86 meters.
You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.
The distance traveled can be calculated by finding the area under the velocity-time graph. The slope of the graph at any point represents the acceleration of the object. The steeper the slope, the greater the acceleration.
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
The distance traveled by the body can be calculated using the equation s = (1/2)at^2, where s is the distance, a is the acceleration, and t is the time taken to reach velocity v from rest.
Formula for distance traveled with constant acceleration is: S = v0t + at2 / 2. Knowing the distance, time and that initial velocity is zero: S = at2 / 2, a = 2S / t2, or numerically: a = 804 / 36 = 22.33 m/s2 Expressing that in terms of g(=9.81 m/s2): a = 2.28 g
because top hat
Yes, the marble's acceleration increased as it traveled down the ramp because the force of gravity acting on it remained constant, but the distance covered by the marble increased. This results in a higher acceleration due to the increased speed gained as it moved farther down the ramp.
The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.
It depends on the rate of acceleration. A top fuel dragster can accelerate at 160 ft/s2. That means it can hit 30 mph (44 ft/s) in about 0.3 seconds. From a standing start, assuming constant acceleration, it will have traveled only about 20 feet. Your mileage may vary.
In the first 2 seconds, the velocity of the ball would be given by v = at, where a is the acceleration. Given it traveled 2 meters in 2 seconds, we can use the equation s = (1/2)at^2 to find the acceleration which is 1 m/s^2. So, after 3 seconds, the ball will travel an additional 3 * 1 = 3 meters.
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