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When is acceleration equals half of the sum of initial and final velocities?
If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.
How far in meters does a person travel in coming to a complete stop in 36 rm ms at a constant acceleration of 60g?
The distance traveled in meters can be calculated using the equation: distance = (velocity^2) / (2 * acceleration). The acceleration should be converted from g to m/s^2 by multiplying by 9.81 m/s^2 per g. Plugging in the values, the distance traveled would be approximately 32.86 meters.
How do you find the distance given only the initial velocity traveled time and final velocity?
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.
How is the velocity-time graph related to the distance traveled?
The product of velocity and time yields distance travelled if the velocity is constant for the time in question. If velocity is not constant, one must first calculate the average velocity over a given time period before multiplying it by the time involved.
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
How can one determine the distance traveled by an object based on its acceleration?
To determine the distance traveled by an object based on its acceleration, you can use the formula: distance 0.5 acceleration time2. This formula calculates the distance traveled by an object with a constant acceleration over a certain period of time.
Formula for distance traveled?
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
What is the formula for distance traveled with constant acceleration?
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
What is the acceleration of a ball that is traveling at a constant velocity of fifty miles and has been traveling for over 2 minutes?
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.
When the body starts from rest and attain velocity v in time t with a constant acceleration the distance traveled by the body is?
d = 1/2 a t2 where d is distance traveled a is the constant acceleration t is the time You can calculate the value of "a" by dividing "v" by "t".
When a particular race car can cover a quarter mile track 402 m in 6.00 s starting from a standstill Assuming the acceleration is constant how many g's does the driver experience?
Formula for distance traveled with constant acceleration is: S = v0t + at2 / 2. Knowing the distance, time and that initial velocity is zero: S = at2 / 2, a = 2S / t2, or numerically: a = 804 / 36 = 22.33 m/s2 Expressing that in terms of g(=9.81 m/s2): a = 2.28 g
If a spacecraft traveled in the escape velocity for 3 days. How far would it travel?
The distance traveled would depend on the spacecraft's speed and the escape velocity of the planet. The formula to calculate the distance traveled with constant acceleration is D = (1/2)at^2, where D is distance, a is acceleration, and t is time. By plugging in the values, you can find the distance traveled.
Norma releases a bowling ball from rest it rolls down a ramp with constant acceleration After half a second it has traveled 0.75m how far has it traveled after two seconds?
because top hat
Did the acceleration of the marble increase as it traveled down the ramp?
Yes, the marble's acceleration increased as it traveled down the ramp because the force of gravity acting on it remained constant, but the distance covered by the marble increased. This results in a higher acceleration due to the increased speed gained as it moved farther down the ramp.
What is the equation relating acceleration the distance traveled and the time of fall.?
The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.
How far will a car travel when accelerating to 30 mph?
It depends on the rate of acceleration. A top fuel dragster can accelerate at 160 ft/s2. That means it can hit 30 mph (44 ft/s) in about 0.3 seconds. From a standing start, assuming constant acceleration, it will have traveled only about 20 feet. Your mileage may vary.
