14 AWG is fine for this application.
Wiki User
∙ 13y agoFor a 50-foot run with a 6.3-amp load at 240 volts, you can use 14-gauge wire as it can safely handle up to 15 amps. If you want to take into account voltage drop for longer runs, you may opt for even thicker wire like 12-gauge to minimize power loss. It's always a good idea to consult with a professional electrician for accurate recommendations.
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
Amps * Volts = Watts So, Watts / Volts = Amps 2000 / 240 = 8.333 Amps You should run the circuit on a two pole 15 Amp breaker, using 14 AWG, 2 conductor (plus ground) wire, just so you have a little safety factor in the circuit size.
A 400 watt heater can safely be used on a 15 amp circuit. The size breaker needed for a circuit is determined by the size of the wiring in that circuit. AWG #14 wire requires a 15 amp breaker. AWG # 12 wire requires a 20 amp breaker.
To determine the fuse size needed for a 6000-watt inverter, you would need to divide the power (in watts) by the voltage of the system (e.g., 12V or 24V) to get the current (in amps) drawn by the inverter. For a 12V system, around 500 amps would be required, so you may need a fuse above this value for safety. It's best to consult the inverter's specifications and guidelines to select the appropriate fuse size to protect the system.
To run two 1500 watt heaters in parallel at 240 volts, each heater will draw 6.25 amps (1500 watts / 240 volts = 6.25 amps). Since you have two heaters, you will need a circuit breaker rated for at least 12.5 amps to safely power both heaters. It would be recommended to use a 15 amp circuit breaker to provide some extra capacity and avoid overloading the circuit.
#8 copper
For a 25 amp load at 220 volts over a distance of 75 feet, you will need a 10-gauge wire to ensure safe and efficient electrical conductivity. This wire size allows for minimal voltage drop and meets the necessary ampacity requirements for the circuit. Make sure to consult local electrical codes and regulations before installation.
Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
Each baseboard heater will draw a little over 4 amps at 120 volts or 2 Amps at 240 volts. The total number of baseboards on a circuit will draw the sum of these amps. Keep the load under 80% of the amperage rating of the breaker.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.
To answer this question a voltage needs to be stated. Wire sizing is based on amperage that the wire can safely conduct. I = W/E. Amps = Watts/Volts.