10 AWG in copper.
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
For a 50 feet distance with 120 volts and 12 amps, you should use a 14-gauge wire to ensure electrical safety and efficiency. A 14-gauge wire is rated to handle up to 15 amps for household wiring applications.
Amps * Volts = Watts So, Watts / Volts = Amps 2000 / 240 = 8.333 Amps You should run the circuit on a two pole 15 Amp breaker, using 14 AWG, 2 conductor (plus ground) wire, just so you have a little safety factor in the circuit size.
Looks like You need to run #10 to get 10 amps at 600 feet. You will have a voltage drop. You might only have aprox. 107.676 volts at the end of the run. You will do a little better if you use strand wire. Good luck.
Assuming the service voltage is 240 volts. A 2/0 aluminum conductor, with an insulation factor of 90 degrees C, will limit the voltage drop to 2% or less when supplying 125 amps for 100 feet on a 240 volt system.
#8 copper
Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
For single phase 30 amps at 120 volts you would need a #8 copper wire with an insulation rating of 90 degrees C.
10 guage
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
Each baseboard heater will draw a little over 4 amps at 120 volts or 2 Amps at 240 volts. The total number of baseboards on a circuit will draw the sum of these amps. Keep the load under 80% of the amperage rating of the breaker.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
For a 50 feet distance with 120 volts and 12 amps, you should use a 14-gauge wire to ensure electrical safety and efficiency. A 14-gauge wire is rated to handle up to 15 amps for household wiring applications.
To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.