It depends on whether this is residential or commercial.
Commercial has to be 12 guage in conduit.
A #4 copper conductor will limit the voltage drop to 3% or less when supplying 20 amps for a distance of 250 feet at 120 volts.
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
For a 25 amp load at 220 volts over a distance of 75 feet, you will need a 10-gauge wire to ensure safe and efficient electrical conductivity. This wire size allows for minimal voltage drop and meets the necessary ampacity requirements for the circuit. Make sure to consult local electrical codes and regulations before installation.
Amps * Volts = Watts So, Watts / Volts = Amps 2000 / 240 = 8.333 Amps You should run the circuit on a two pole 15 Amp breaker, using 14 AWG, 2 conductor (plus ground) wire, just so you have a little safety factor in the circuit size.
For a 15 amp circuit over a distance of 300 feet, you would typically need a 14-gauge wire to minimize voltage drop and ensure safe operation. Using a larger wire size, such as 12-gauge, would offer even better performance and safety margin.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
A #4 copper conductor will limit the voltage drop to 3% or less when supplying 20 amps for a distance of 250 feet at 120 volts.
10 guage
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
Wire is sized by the amperage that it is allowed to legally carry. To answer this question the amperage that you need at the garage must be stated.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
That distance you are going to have to install a sub-panel and run AWG # 4 wire and even then you will have a voltage drop of 7.45 volts giving you 232.55 volts at the sub-panel which is acceptable.
#8 copper
Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself
To answer this question a voltage needs to be stated. Wire is sized by the amount of amperage the load takes. W = Amps x Volts. Amps = 650/ volts.
A #8 AWG copper conductor with an insulation factor of 90 degrees C will limit the voltage drop to 2.26% or less when supplying 30 amps for 120 feet on a 220 volt system.