It depends on whether this is residential or commercial.
Commercial has to be 12 guage in conduit.
A #14 copper or #12 aluminium will limit the voltage drop to 3% when supplying 12 amps for 50 feet on a 120 volt system.
10 AWG in copper.
A #4 copper conductor will limit the voltage drop to 3% or less when supplying 20 amps for a distance of 250 feet at 120 volts.
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
You would need at least 3 AWG at 120 volts, giving you a 4.8 percent voltage drop at the maximum load of 37.5 amps (using 30 Amps at the ordinary 80 percent rated capacity of the circuit). For 240 volts you would only need 6 AWG.
Amps * Volts = Watts So, Watts / Volts = Amps 2000 / 240 = 8.333 Amps You should run the circuit on a two pole 15 Amp breaker, using 14 AWG, 2 conductor (plus ground) wire, just so you have a little safety factor in the circuit size.
10 AWG in copper.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
A #4 copper conductor will limit the voltage drop to 3% or less when supplying 20 amps for a distance of 250 feet at 120 volts.
10 guage
Wire is sized by the amperage that it is allowed to legally carry. To answer this question the amperage that you need at the garage must be stated.
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
That distance you are going to have to install a sub-panel and run AWG # 4 wire and even then you will have a voltage drop of 7.45 volts giving you 232.55 volts at the sub-panel which is acceptable.
You would need at least 3 AWG at 120 volts, giving you a 4.8 percent voltage drop at the maximum load of 37.5 amps (using 30 Amps at the ordinary 80 percent rated capacity of the circuit). For 240 volts you would only need 6 AWG.
#8 copper
Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself