0
What else can I help you with?
What is -3r-13 r equals 2 is?
-16r=2 divide both sides by -16 and your answer is -1/8
How do you Factor 3r squared equals 13r plus 10?
(3r + 2)(r - 5)
Solve 4r plus 3 equals 3r- 2 for r?
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
What is the solution for 3r - 9r equals 18?
3r - 9r = 18 wright equaton -6r = 18 combine like terms r = -3 solve
What is the sum of r - 10 and 100 - 3r?
r - 10 + 100 - 3r = -2r + 90
What is the answer for this math algebra problem 3r-2 for r equals 65?
3r-2 for r=65
What is -3r-13 r equals 2 is?
-16r=2 divide both sides by -16 and your answer is -1/8
How do you solve the equation 17 equals 13-3r?
17 = 13 - 3r Subtract 13 from bith sides: 4 = -3r Divide both sides by -3 : -4/3 = r or r = -1.3...
What is 3r-r equals 12?
3r-r equals 12 = -9
How do you Factor 3r squared equals 13r plus 10?
(3r + 2)(r - 5)
What is -3r-13r equals 2?
-3r-13r = 2 -16r = 2 or 16r = -2 r = -(2/16) = -(1/8)
What is the answer for 3r-13r equals 2?
so -10r = 2 so r = -0.2
Solve 4r plus 3 equals 3r- 2 for r?
4r +3 = 3r-2 r + 3=-2 r=-5 basically collect terms so that you get one coefficient of r (in this case 4r on one side and 3r on the other. To get the three r over to the other side you subtract 3r on both sides.) Then r+ 3=-2, so that's simple algebraic manipulation.
What is r in this equation and how do you do it minus 5 equals 7 plus 3r?
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
What is -5 equals 7 plus 3r?
If: -5 = 7+3r then the value of r works out as -4
13r plus 10 equals 5r-46?
3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
