8,10,12
16, 17 and 18
the answer is 6
6 and 8. 6 * 8 = 48 6 * 6 = 36 48 - 36 = 12
Let the 3 consecutive number be represented by n, (n + 1) and (n + 2) Then, n(n + 1) + 37 = (n + 2)2 n2 + n + 37 = n2 + 4n + 4 3n = 33 n = 11 The three numbers are 11, 12 and 13.
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
5,6,7
11,12,13
8,10,12
1, 3, 5
16, 17 and 18
12, 13 and 14
5, 6 and 7
8, 9, and 10
14, 15, 16
4, 6, and 8
3, 5, 7