6 -- abc, acb, bac, bca, cab, cba
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
There are 216 PERMUTATIONS, but there are only 56 combinations.The combination ABC is the same as ACB, BAC, BCA, CAB and CBA.The 56 combinations are6 combinations on 3 of the same.30 combinations of 2 of one and 1 of anotherand20 combinations of 1 each.
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
Sadly, parentheses are not retained when the question is stored,so we can't tell where you meant for them to be.Here are a couple of alternatives:(A/B)/C = A/BCA/(B/C) = A x C/B = AC/B
abc
In order to find length BC the length of AC or length of the hypotenuse must be given
First draw a triangle with vertices A, B, and C. Let's let C be at the top and B and A the base of the triangle. A' and B' are on the line drawn parallel to the base and through point vertex C. Place A' on the right of C and B' on the left of C. Of course it works for any triangle, but I am trying to make the picture easy so then you can generalize.if ABC is a triangle then
6 -- abc, acb, bac, bca, cab, cba
Yeah u can do it after 12th.......
There can be 4 different non-repeating allele combinations in the gametes of a person with genotype AABBCc: ABC, ACB, BAC, and BCA.
Your best bet would be to contact the university directly.
BCA sort codes
BCA Semarang
yes.you can
what is the time table of bca examination
BCA Research was created in 1949.