It is possible.
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6 -- abc, acb, bac, bca, cab, cba
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
There are 216 PERMUTATIONS, but there are only 56 combinations.The combination ABC is the same as ACB, BAC, BCA, CAB and CBA.The 56 combinations are6 combinations on 3 of the same.30 combinations of 2 of one and 1 of anotherand20 combinations of 1 each.
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
Sadly, parentheses are not retained when the question is stored,so we can't tell where you meant for them to be.Here are a couple of alternatives:(A/B)/C = A/BCA/(B/C) = A x C/B = AC/B